Webfelse if (b->lchild==NULL&&b->rchild==NULL) return 1; else { n=leafs (b->lchild); m=leafs (b->rchild); return n+m; } (6)主函数 main (),功能是给出测试数据值,建立测试数据值的顺序表,调用 creat 函数、preorder 函数、inorder 函数、postorder 函数 high、函数 nodes 函数、leafs 函数实现问题要求。 Web9 jul. 2024 · 逻辑表达式从终端输入,长度不超过一行。. 逻辑运算符包括“ ”,“&”和“~”,分别表示或,与和非,运算优先程度递增,但可由括号改变,即括号内运算优先。. 逻辑变元为大写字母。. 表达式中任何地方都可以含有一个或多个空格符。. 若是重言式或矛盾 ...
实现二叉树各种遍历算法-阿里云开发者社区 - Alibaba Cloud
Web15 nov. 2024 · if (b==NULL) return 0; else if (b->lchild==NULL && b->rchild==NULL) return 1; else { num1=Nodes(b->lchild); num2=Nodes(b->rchild); return … Web27 aug. 2013 · if (b1->lchild!=NULL) m=bt_similar (b1->lchild,b2->lchild); if (b1->rchild!=NULL) m=bt_similar (b1->rchild,b2->rchild); You should have: if (b1->lchild!=NULL) m = bt_similar (b1->lchild,b2->lchild); if (b1->rchild!=NULL) m = m && bt_similar (b1->rchild,b2->rchild); Share Improve this answer Follow edited Aug 27, … temperley vs san martin
(数据结构课程设计)二叉树_百度文库
Well, arguably the best is: if (b1 == b2) return true; if (b1 == NULL b2 == NULL) return false; - as this also optimises the comparison in case the tree is being compared with itself. I personally find this more comprehensible than the two suggestions above, also, but it does come down to personal taste I guess. Webif ((b->lchild==NULL && b->rchild!=NULL) //单分支的结点. (b->lchild!=NULL && b->rchild==NULL) return singleodes(b->lchild)+ singleodes(b->rchild)+1; 结果一. 题目. … Web25 aug. 2012 · #include#include#includeusing namespace std;#define M temperli cam kesilir mi